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"오라클 오브젝트"의 두 판 사이의 차이

DB CAFE

(오라클 오브젝트)
 
(다른 사용자 한 명의 중간 판 하나는 보이지 않습니다)
1번째 줄: 1번째 줄:
= 오라클 오브젝트 =
+
= 오브젝트 =
== 오브젝트 ==
+
== 사용자별 오브젝트 ==
 
<source lang="sql"> SELECT OWNER AS "OWNER"
 
<source lang="sql"> SELECT OWNER AS "OWNER"
  
16번째 줄: 16번째 줄:
  
 
FROM DBA_OBJECTS GROUP BY OWNER; </source>
 
FROM DBA_OBJECTS GROUP BY OWNER; </source>
 +
[[Category:oracle]]

2019년 12월 22일 (일) 15:05 기준 최신판

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1 오브젝트[편집]

1.1 사용자별 오브젝트[편집]

SELECT OWNER AS "OWNER"

         ,SUM(DECODE(OBJECT_TYPE, 'TABLE', 1, 0)) AS "TABLE"
         ,SUM(DECODE(OBJECT_TYPE, 'INDEX', 1, 0)) AS "INDEX"
         ,SUM(DECODE(OBJECT_TYPE, 'SYNONYM', 1, 0)) AS "SYNONYMS"
         ,SUM(DECODE(OBJECT_TYPE, 'SEQUENCE', 1, 0)) AS "SEQUENCES"
         ,SUM(DECODE(OBJECT_TYPE, 'VIEW', 1, 0)) AS "VIEWS"
         ,SUM(DECODE(OBJECT_TYPE, 'CLUSTER', 1, 0)) AS "CLUSTERS"
         ,SUM(DECODE(OBJECT_TYPE, 'DATABASE LINK', 1, 0)) AS "DBLINKS"
         ,SUM(DECODE(OBJECT_TYPE, 'PACKAGE', 1, 0)) AS "PACKAGES"
         ,SUM(DECODE(OBJECT_TYPE, 'PACKAGE BODY', 1, 0)) AS "PACKAGE_BODY"
         ,SUM(DECODE(OBJECT_TYPE, 'PROCEDURE', 1, 0)) AS "PROCEDURES"
         ,SUM(DECODE(OBJECT_TYPE, 'FUNCTION', 1, 0)) AS "FUNCTION"

FROM DBA_OBJECTS GROUP BY OWNER;